What is the slope of the line passing through the following points: $(- \frac{3}{2}, \frac{5}{6}); (\frac{1}{3}, - \frac{1}{12})$ $(-3/2 , 5/6) ; (1/3 , -1/12)$ ?

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What is the slope of the line passing through the following points: $(- \frac{3}{2}, \frac{5}{6}); (\frac{1}{3}, - \frac{1}{12})$ $(-3/2 , 5/6) ; (1/3 , -1/12)$ ?

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Answer 1 · 2016-04-05T10:12:32

slope $m = - \frac{1}{2}$ $m=-1/2$

Explanation:

Let $P_{1} (x_{1}, y_{1}) = (- \frac{3}{2}, \frac{5}{6})$ $P_1(x_1, y_1)=(-3/2, 5/6)$
Let $P_{2} (x_{2}, y_{2}) = (\frac{1}{3}, - \frac{1}{12})$ $P_2(x_2, y_2)=(1/3, -1/12)$

The formula to compute slope

$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ $m=(y_2-y_1)/(x_2-x_1)$

$m = \frac{- \frac{1}{12} - \frac{5}{6}}{\frac{1}{3} - - \frac{3}{2}}$ $m=(-1/12-5/6)/(1/3--3/2)$

After simplification

$m = - \frac{1}{2}$ $m=-1/2$

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What is the slope of the line passing through the following points: $(- \frac{3}{2}, \frac{5}{6}); (\frac{1}{3}, - \frac{1}{12})$ $(-3/2 , 5/6) ; (1/3 , -1/12)$ ?

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Explanation:

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What is the slope of the line passing through the following points: $(- \frac{3}{2}, \frac{5}{6}); (\frac{1}{3}, - \frac{1}{12})$ $(-3/2 , 5/6) ; (1/3 , -1/12)$ ?