What is the slope of the line perpendicular to the line represented by the equation 2x+4y=122x+4y=12?

1 Answer
Divya Prakash S. · Tony B
Apr 10, 2018

The slope of the line perpendicular to the line 2x+4y=122x+4y=12 is 2.

Explanation:

2x + 4y=122x+4y=12
=>y= (12 - 2x)/4⇒y=12−2x4
=>y= 3 - x/2⇒y=3−x2
=>y= -x/2 + 3⇒y=−x2+3
This is in the form of y=mx+by=mx+b where m is the slope.
There the slope of the above line is -1/2−12.
Since, the slope of line perpendicular to a given line is the negative reciprocal of it.
Therefore, the slope of the required perpendicular line
= -1/(-1/2)=−1−12
=-(-2)=−(−2)
=2=2

Related questions
See all questions in Slope
Impact of this question
7224 views around the world
You can reuse this answer
Creative Commons License