Question

What is the slope of the line perpendicular to the line represented by the equation `2x+4y=12`?

Answer 1

The slope of the line perpendicular to the line `2x+4y=12` is 2.

Explanation:

`2x + 4y=12`
`=>y= (12 - 2x)/4`
`=>y= 3 - x/2`
`=>y= -x/2 + 3`
This is in the form of `y=mx+b` where m is the slope.
There the slope of the above line is `-1/2`.
Since, the slope of line perpendicular to a given line is the negative reciprocal of it.
Therefore, the slope of the required perpendicular line
`= -1/(-1/2)`
`=-(-2)`
`=2`