What is the slope of the line perpendicular to the line $y = - 5 x + 9$ $y=-5x+9$ ?

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What is the slope of the line perpendicular to the line $y = - 5 x + 9$ $y=-5x+9$ ?

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Answer 1 · 2015-02-05T17:06:21

Remember that the slopes of perpendicular lines are negative reciprocals.

First find the slope of your original equation. Since $y = - 5 x + 9$ $y=-5x+ 9$ is written in slope intercept form, $y = m x + b$ $y=mx+b$ , we find that the slope is $- 5$ $-5$

Now find the negative reciprocal of $- 5$ $-5$

We can rewrite $- 5$ $-5$ as $- \frac{5}{1}$ $-5/1$ .

The negative reciprocal of this will be $\frac{1}{5}$ $1/5$

Thus the slope of the line perpendicular to the line $y = - 5 x + 9$ $y=-5x+9$ is $\frac{1}{5}$ $1/5$

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What is the slope of the line perpendicular to the line $y = - 5 x + 9$ $y=-5x+9$ ?

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