What is the slope of the line perpendicular to #y=-3/2x+15 #?

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Answer 1 · 2016-03-04T03:13:53

The slope of a perpendicular line is equal to the negative reciprocal of the slope of the given equation

We know that the slope of this equation is #-3/2#

So, we take the reciprocal, which means that we flip the fraction over

#-2/3#

But we take the negative reciprocal, so we add a negative sign

#- (-2/3)#

This is equal to #2/3#

So the slope of the perpendicular line is #2/3#