What is the slope of the tangent line of # x^2/(x-y^3) = C #, where C is an arbitrary constant, at #(-2,1)#?
1 Answer
Jan 2, 2016
Explanation:
Find the implicit derivative of the function.
Use the product rule.
#((x-y^3)d/dx(x^2)-x^2d/dx(x-y^3))/(x-y^3)^2=0#
Remember that differentiating a
#(2x(x-y^3)-x^2(1-3y^2dy/dx))/(x-y^3)^2=0#
Plug in
#(2(-2)(-2-1^3)-(-2)^2(1-3(1)^2dy/dx))/(-2-1^3)^2=0#
Notice that the denominator can be cancelled out. Continue simplification of numerator.
#(-4)(-3)-(4)(-2)dy/dx=0#
#12+8dy/dx=0#
#dy/dx=-3/2#
The slope of the tangent line is