What is the solution for the system of equations $3 y + 2 x = 4$ $3y + 2x = 4$ and $2 y - 6 x = - 12$ $2y-6x=-12$ ?

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What is the solution for the system of equations $3 y + 2 x = 4$ $3y + 2x = 4$ and $2 y - 6 x = - 12$ $2y-6x=-12$ ?

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Answer 1 · 2018-04-19T17:16:10

Multiplying the first by 3 yields $9 y + 6 x = 12$ $9y+6x=12$ , adding to the second $11 y = 0$ $11y=0$ so $y = 0$ $y=0$ and $x = 2$ $x=2$ .

Answer 2 · 2018-04-19T17:18:02

$x = 2$ $x=2$
$y = 0$ $y=0$

Explanation:

$3 y + 2 x = 4$ $3 y+2 x=4$
$2 y - 6 x = - 12$ $2 y- 6 x=-12$

Multiply the first equation by 3:
$9 y + 6 x = 12$ $9 y+6 x=12$
Sum equation (1.)+(2.):
$9 y + 6 x = 12$ $9 y+6 x=12$ |+
$2 y - 6 x = - 12$ $2 y- 6 x=-12$
$9 y + 2 y + 6 x - 6 x = 12 - 12$ $9 y+ 2 y +6 x-6 x=12-12$
$11 y + 0 = 0$ $11 y+0=0$ $\Rightarrow$ $=>$ $y = 0$ $y=0$

Put $y = 0$ $y=0$ in one equation for example the first:
$3 \cdot 0 + 2 x = 4$ $3*0+2 x=4$
$x = \frac{4}{2} = 2$ $x=4/2=2$

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What is the solution for the system of equations $3 y + 2 x = 4$ $3y + 2x = 4$ and $2 y - 6 x = - 12$ $2y-6x=-12$ ?

2 Answers

Explanation:

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What is the solution for the system of equations $3 y + 2 x = 4$ $3y + 2x = 4$ and $2 y - 6 x = - 12$ $2y-6x=-12$ ?