What is the solution of the mentioned problem?

Question

Prove that,#tan3atan2atana=tan3a-tan2a-tana#

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Answer 1 · 2017-12-18T19:19:03

See below.

#tan(3a)tan(2a)tana=tan(3a)-tan(2a)-tana#

is not an identity so we cannot prove it.

We can solve as an equation. In this case we obtain

#tan(3a)tan(2a)tana-tan(3a)+tan(2a)+tana=2(2+sec(2a))tana = 0#

and the solutions are those #a# such that

#{(sec(2a) + 2=0),(tan(a)=0):}# or

#{(cos(2a) + 1/2=0),(tan(a)=0):}#