What is the solution to the inequality $7 x - 5 \geq x + 1$ $7x - 5 ≥ x + 1$ ?

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What is the solution to the inequality $7 x - 5 \geq x + 1$ $7x - 5 ≥ x + 1$ ?

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Answer 1 · 2016-07-06T04:54:54

$x \geq 1$ $x>=1$ , or, in the interval form, $x \in [1, \infty)$ $x in [1,oo)$

Explanation:

Adding $(- x + 5)$ $(-x+5)$ on both sides, we get,
$7 x - 5 - x + 5 \geq x + 1 - x + 5 \Rightarrow 6 x \geq 6$ $7x-5-x+5>=x+1-x+5 rArr 6x>=6$

Next, we multiply on both side by $\frac{1}{6}$ $1/6$ , noting that $\frac{1}{6}$ $1/6$ being $+ v e$ $+ve$ , the multiplication will not affect the order of the inequality.

Hence, we have, $x \geq 1$ $x>=1$ , or, in the interval form, $x \in [1, \infty)$ $x in [1,oo)$

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What is the solution to the inequality $7 x - 5 \geq x + 1$ $7x - 5 ≥ x + 1$ ?

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