What is the solution to the system #x+y=2# and #x-y=6#?

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Answer 1 · 2018-03-06T03:17:02

#x = 4" and " y = -2 #

Add the two equations eliminating #y# to solve for #x#

# " "x + y = 2 #
# +x -y = 6#
# 2x + 0y = 8 #

# 2x = 8" " # divide each side by 2

# (2x)/2 = 8/2 #

# x = 4 " "# Substitute 4 for x and solve for y

# 4 + y = 2 " "# subtract 4 from each side

# 4 -4 + y = 2 -4" " # This gives

# y = -2 #