What is the specific heat capacity of a metal if it requires 178.1 J to change the temperature to 15.0 g of the metal from 25.00 C to 32.00 C?

1 Answer
Jul 1, 2016

"1.70 J g"^(-1)""^@"C"^(-1)

Explanation:

When a problem asks you to find a substance's specific heat, c, it's essentially telling you to find how much heat is needed in order to increase the temperature of "1 g" of said substance by 1^@"C".

In your case, you know that you need "178.1 J" in order to increase the temperature of "15.0 g" of your unknown metal by 7^@"C", since

DeltaT = 32.00^@"C" - 25.00^@"C" = 7.00^@"C"

So, how much heat would be needed to increase the temperature of "1 g" of this metal by 7.00^@"C ?"

1 color(red)(cancel(color(black)("g"))) * "178.1 J"/(15.0color(red)(cancel(color(black)("g")))) = "11.873 J"

Since this much heat is needed to increase the temperature of "1 g" by 7.00^@"C", it follows that you can increase temperature by 1^@"C" by adding

1color(red)(cancel(color(black)(""^@"C"))) * "11.873 J"/(7.00color(red)(cancel(color(black)(""^@"C")))) = "1.70 J"

Since you need "1.70 J" to increase the temperature of "1 g" of this metal by 1^@"C", you can say that the metal's specific heat will be

c = color(green)(|bar(ul(color(white)(a/a)color(black)("1.70 J g"^(-1)""^@"C"^(-1))color(white)(a/a)|))) -> rounded to three sig figs

ALTERNATIVELY

You can also use the following equation

color(blue)(|bar(ul(color(white)(a/a)q = m * c * DeltaTcolor(white)(a/a)|)))" ", where

q - the amount of heat released
m - the mass of the sample
c - the specific heat of the substance
DeltaT - the change in temperature, defined as the difference between the final temperature and the initial temperature

Rearrange to solve for c

q = m * c * DeltaT implies c = q/(m * DeltaT)

Plug in your values to find

c = "178.1 J"/("15.0 g" * 7.00^@"C") = color(green)(|bar(ul(color(white)(a/a)color(black)("1.70 J g"^(-1)""^@"C"^(-1))color(white)(a/a)|)))