What is the #sqrt(-25)#? Precalculus Complex Numbers in Trigonometric Form Complex Number Plane 1 Answer George C. Aug 14, 2016 #sqrt(-25) = 5i# Explanation: #-25# has two square roots #5i# and #-5i#, but the expression #sqrt(-25)# denotes the principal square root, which by convention is #5i#. In general, if #x < 0# then #sqrt(x) = (sqrt(-x))i#. Hence in our example: #sqrt(-25) = (sqrt(25))i = (sqrt(5^2))i = 5i# Answer link Related questions What is the complex number plane? Which vectors define the complex number plane? What is the modulus of a complex number? How do I graph the complex number #3+4i# in the complex plane? How do I graph the complex number #2-3i# in the complex plane? How do I graph the complex number #-4+2i# in the complex plane? How do I graph the number 3 in the complex number plane? How do I graph the number #4i# in the complex number plane? How do I use graphing in the complex plane to add #2+4i# and #5+3i#? How do I use graphing in the complex plane to subtract #3+4i# from #-2+2i#? See all questions in Complex Number Plane Impact of this question 13351 views around the world You can reuse this answer Creative Commons License