Question

What is the standard form of `y= (2x-3)(4x-4)^2`?

Answer 1

`y=32x^3-112x^2+128x-48`

Explanation:

`y=(2x-3)(4x-4)(4x-4)`
`y=(8x^2-8x-12x+12)(4x-4)`
`y=(8x^2-20x+12)(4x-4)`
`y=32x^3-80x^2+48x-32x^2+80x-48`
`y=32x^3-112x^2+128x-48`