What is the standard form of $y = (9 x^{2} + 5) (x - 1)$ $y= (9x^2+5)(x-1)$ ?

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What is the standard form of $y = (9 x^{2} + 5) (x - 1)$ $y= (9x^2+5)(x-1)$ ?

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Answer 1 · 2017-02-03T15:48:17

$y = 9 x^{3} - 9 x^{2} + 5 x - 5$ $y=9x^3-9x^2+5x-5$

Explanation:

$a a a a a a a a a a a a a a a$ $color(white)(aaaaaaaaaaaaaaa)$ $9 x^{2} + 5$ $9x^2+5$
$a a a a a a a a a a a a a a a$ $color(white)(aaaaaaaaaaaaaaa)$ $x - 1$ $x-1$
$a a a a a a a a a a a a a a a$ $color(white)(aaaaaaaaaaaaaaa)$ $- - -$ $---$
$a a a a a a a a a a a a a a a$ $color(white)(aaaaaaaaaaaaaaa)$ $9 x^{3} + 5 x$ $9x^3+5x$
$a a a a a a a a a a a a a a a a$ $color(white)(aaaaaaaaaaaaaaaa)$ $- 9 x^{2} - 5$ $-9x^2-5$
$a a a a a a a a a a a a a a a a$ $color(white)(aaaaaaaaaaaaaaaa)$ $- - - - -$ $-----$
$a a a a a a a a a a a a a a a$ $color(white)(aaaaaaaaaaaaaaa)$ $9 x^{3} - 9 x^{2} + 5 x - 5$ $9x^3-9x^2+5x-5$

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What is the standard form of $y = (9 x^{2} + 5) (x - 1)$ $y= (9x^2+5)(x-1)$ ?

1 Answer

Explanation:

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What is the standard form of y= (9x^2+5)(x-1) y=(9x2+5)(x−1)y= (9x^2+5)(x-1) ?

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Explanation:

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What is the standard form of $y = (9 x^{2} + 5) (x - 1)$ $y= (9x^2+5)(x-1)$ ?