What is the the volume occupied by 2.34 g of carbon dioxide gas at STP?

2 Answers
May 6, 2016

V=1.18L

Explanation:

In order to solve this problem we would use the Ideal Gas Law formula PV=nRT

P= Pressure in atm
V= Volume in L
n= moles
R= Ideal Gas Law Constant
T= Temp in K

STP is Standard Temperature and Pressure which has values of
1atm and 273K

2.34gCO2 must be converted to moles

2.34gCO2x1mol44gCO2=0.053mols

P=1atm
V=???L
n=0.053mols
R=0.0821atmLmolK
T=273K

PV=nRT becomes

V=nRTP

V=0.053mols(0.0821atmLmolK)(273K)1atm

V=1.18L

May 7, 2016

1.18L

Explanation:

Alternative solution:

Calculate how many moles 2.34g CO2 is

2.34g1mol44gCO2=0.053mol

Simple mole ratios tell us that 1 mol of any gas at STP is 22.4L, but since we only have 0.053mol, we times 22.4Lmol by 0.053mol.

22.4Lmol0.053mol=1.18L