What is the total pressure of a container that has $N H_{3} (g)$ $NH_3(g)$ exerting a pressure of 34 torr, $N_{2} (g)$ $N_2(g)$ exerting a pressure of 225 torr, and $H_{2} O (g)$ $H_2O(g)$ exerting a pressure of 55 torr?

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Answer 1 · 2017-05-16T00:29:28

$314 t o r r$ $314 t o r r$

According to Dalton's law of partial pressures,

$P_(t otal) = P_1 + P_2 + P_3 ...$

So the total pressure of the system is merely the partial pressures of each component added together:

$P_(t otal) = P_(NH_3) + P_(N_2) + P_(H_2O)$

$= 34 t o r r + 225 t o r r + 55 t o r r = 314 t o r r$

What is the total pressure of a container that has NH_3(g)NH3(g)NH_3(g) exerting a pressure of 34 torr, N_2(g)N2(g)N_2(g) exerting a pressure of 225 torr, and H_2O(g)H2O(g)H_2O(g) exerting a pressure of 55 torr?