step 1:Find cross product of two vector the cross product of two vector in the same plane is perpendicular to the plane let →C=→AX→B →C=i(ay⋅bz−az⋅by)−j(ax⋅bz−az⋅bx)+k(ax⋅by−ay⋅bx) →c=i(−10)−j(−3)+k(24) →C=−10i+3j+24k step 2:Find magnitude of the vector of →C ||c||=√(−10)2+32+242 ||c||=√100+9+576 ||c||=√685 step3:use:→C||c|| −10i+3j+24k√685 (−10√685⋅i+3√685⋅j+24√685.k)