What is the value of #f^'(2)#?
Given, #f(x)=int_1^(x^3)# (1/(1+lnt))dt
Given,
2 Answers
Apr 3, 2018
Explanation:
We have:
#f(x) = int_1^(x^3) 1/(1 +lnt) dt#
By the chain rule
#f'(x) = (3x^2)/(1 + ln(x^3)) #
Thus
#f'(2) = (3(2)^2)/(1 + ln(8))#
#f'(2) = 12/(1 +ln8)#
Hopefully this helps!
Apr 3, 2018
Explanation:
Suppose that,
Further, by the Fundamental Theorem of Calculus,