What is the value of $f (x) = - x^{2} + 8 x - 6$ $f(x) = -x^2 + 8x - 6$ when $f (2)$ $f(2)$ ?

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Answer 1 · 2016-04-14T02:45:11

$f (2) = 6$ $f(2)=6$

Given equation $f (x) = - x^{2} + 8 x - 6$ $f(x)=-x^2+8x-6$ and we need to find $f (2)$ $f(2)$

$f (2)$ $f(2)$ means that $x = 2$ $x=2$

So, we need to substitute $x = 2$ $x=2$ into $f (x) = - x^{2} + 8 x - 6$ $f(x)=-x^2+8x-6$ to get $f (2)$ $f(2)$ ;

$f (x) = - x^{2} + 8 x - 6$ $f(x)=-x^2+8x-6$

$f (2) = - {(2)}^{2} + 8 (2) - 6$ $f(2)=-(2)^2+8(2)-6$

$f (2) = - 4 + 16 - 6$ $f(2)=-4+16-6$

$f (2) = 6$ $f(2)=6$

What is the value of f(x)=−x2+8x−6f(x) = -x^2 + 8x - 6 when f(2)f(2)?