Question

What is the vertex of `y= 2x^2-x-3-4(x-1)^2`?

Answer 1

`"Vertex": (7/4, -7/8)`

Explanation:

`y= 2x^2-x-3-4(x-1)^2`
`y = 2x^2-x-3-4x^2+8x-4`
`y = -2x^2 + 7x - 7`

`f(x) = ax^2 + bx + c " : x vertex" = (-b)/(2a)`

`(-b)/(2a) = (-7)/(2(-2) = 7/4`

`y = -2(7/4)^2 + 7(7/4) - 7 = (-7)/8`