Question

What is the vertex of `y = 3(x - 2)^2 + 5`?

Answer 1

The vertex is at:(2, 5)

Explanation:

`y=a(x-h)^2+k` => equation of parabola in vertex form where: (h, k)is the vertex.
So in this case:
`y=3(x−2)^2+5` => the vertex is at:(2, 5)