Question

What is the vertex of `y=-x^2-4x-3`?

Answer 1

`(-2, 1)`

Explanation:

Rearrange the expression into the form `y = (x - a)^2 + b`. The vertex is then `(a, b)`. a is half the coefficient of x in the original equation.
`y = -(x^2 + 4x +3)`
`y = -((x+2)^2 -1)`
`y = -(x +2)^2 + 1`
Vertex is `(-2, 1)`