What is the vertical asymptote of $(x + 4)/(x^2+x-6)$ ?

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Answer 1 · 2015-09-01T17:09:40

There are two vertical asymptotes: $x=2$ and $x=-3$

The denominator $x^2+x-6$ is $0$ when $x$ is $2$ or $-3$ .

Neither of these values make the numerator equal to $0$ , so we cannot reduce (simplify) the fraction.

Therefore, we have vertical asymptotes at $2$ and at $-3$ .

The equations of the lines are $x=2$ and $x=-3$ .

What is the vertical asymptote of (x + 4)/(x^2+x-6)(x + 4)/(x^2+x-6)?