What is the volume (in liters) of 2.5 moles of oxygen gas measured at 250C and a pressure of 104.5 kpa?

1 Answer
Jul 9, 2016

V=(nRT)/P ~= 100*L

Explanation:

Of course you must choose the appropriate Gas constant. Here it is 8.314*L*kPa*K^-1*mol^-1.

"Volume" =(2.5*cancel(mol)xx8.314*L*cancel(kPa)*cancel(K^-1)*cancel(mol^-1)xx523*cancelK)/(104.5*cancel(kPa))

= ??L