What is the volume (in liters) of 2.5 moles of oxygen gas measured at 250C and a pressure of 104.5 kpa?

1 Answer
Jul 9, 2016

V=(nRT)/PV=nRTP ~= 100*L100L

Explanation:

Of course you must choose the appropriate [Gas constant.](https://en.wikipedia.org/wiki/Gas_constant) Here it is 8.314*L*kPa*K^-1*mol^-18.314LkPaK1mol1.

"Volume"Volume =(2.5*cancel(mol)xx8.314*L*cancel(kPa)*cancel(K^-1)*cancel(mol^-1)xx523*cancelK)/(104.5*cancel(kPa))

= ??L