What is the volume, in liters, of 5.0 mol of Ne gas at STP?

1 Answer
Mar 24, 2018

V_(Ne) = 22.41 L

Explanation:

"We use the ideal gas law,"

color(orange)(PV=nRT)

"We know the conditions for STP are the following,"

P=101.325 kPa

V=?

n = 1.0 mol

R=8.314

T=273.15 K

Plug in your values.

color(orange)(V_(Ne)=(nRT)/(P)

=((1.0mol)(8.314)(273.15))/(101.325)

=((1.0mol)(8.314)(273.15))/(101.325)

=(2270.9691)/(101.325)

V_(Ne) = 22.41 L

"This is true because the volume of an ideal gas is 22.41 L/mol at STP."