What is the volume occupied by 51.0 g of ammonia (NH_3) gas at STP?
1 Answer
The boiling point of ammonia is
Hence, ammonia is a gas at STP.
Assuming ideality, we use the ideal gas law as
\mathbf(PV = nRT) where:
P is the pressure. Let's use"1 bar" .V is the volume in"L" .n is the\mathbf("mol") s of gas.R = 0.083145 ("L"cdot"bar")/("mol"cdot"K") is the universal gas constant for your units.T is the temperature in"K" .
V = (nRT)/P
To get
51.0 cancel("g") xx ("1 mol NH"_3)/(17.0307 cancel("g NH"_3))
= "2.995 mols"
Finally, solve for the volume.
color(blue)(V) = ((2.995 cancel("mols"))(0.083145 ("L"cdotcancel("bar"))/(cancel("mol")cdotcancel("K")))(273.15 cancel("K")))/cancel("1 bar")
= color(blue)("68.01 L")
CHALLENGE: Can you use the density of ammonia gas,