What is the volume of 0.140 g of $C_{2} H_{2} F_{4}$ $C_2H_2F_4$ vapor at 1.06 atm and 14.2°C?

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What is the volume of 0.140 g of $C_{2} H_{2} F_{4}$ $C_2H_2F_4$ vapor at 1.06 atm and 14.2°C?

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Answer 1 · 2018-03-29T16:50:17

Approx. $31 \cdot m L$ $31*mL$ ....

Explanation:

We use Ideal Gas equation....

$V = \frac{n R T}{P} \equiv \frac{\frac{0.140 \cdot g}{102.04 \cdot g \cdot m o l^{- 1}} \times 0.0821 \cdot \frac{L \cdot a t m}{K \cdot m o l} \times 287.35 \cdot K}{1.06 \cdot a t m} = ? ? \cdot L$ $V=(nRT)/P-=((0.140*g)/(102.04*g*mol^-1)xx0.0821*(L*atm)/(K*mol)xx287.35*K)/(1.06*atm)=??*L$

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What is the volume of 0.140 g of $C_{2} H_{2} F_{4}$ $C_2H_2F_4$ vapor at 1.06 atm and 14.2°C?

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What is the volume of 0.140 g of C2H2F4C_2H_2F_4 vapor at 1.06 atm and 14.2°C?

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What is the volume of 0.140 g of $C_{2} H_{2} F_{4}$ $C_2H_2F_4$ vapor at 1.06 atm and 14.2°C?