What is the volume of 2.0 moles of an ideal gas at 290 K and 2.8 atm?

Question

2365 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-01-31T10:49:04

#0.016996651m^3#

here,

#temperature,T=color(red)(290K)#

#pressure=2.8atm=2.8xx101325pa=color(red)(283710pa)#

#n=color(red)(2.0mol es)#

for ideal gas, we know,

#PV=nRT#

#V=(nRT)/P#

#V=(2.0mol exx8.314Nmmol e^(-1)K^(-1)xx290K)/(283710Nm^(-2)#

#=0.016996651m^3#