What is the volume of 2.0 moles of an ideal gas at 290 K and 2.8 atm?

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Answer 1 · 2016-01-31T10:49:04

$0.016996651m^3$

here,

$temperature,T=color(red)(290K)$

$pressure=2.8atm=2.8xx101325pa=color(red)(283710pa)$

$n=color(red)(2.0mol es)$

for ideal gas, we know,

$PV=nRT$

$V=(nRT)/P$

$V=(2.0mol exx8.314Nmmol e^(-1)K^(-1)xx290K)/(283710Nm^(-2)$

$=0.016996651m^3$