What is the volume of 2.10 moles of chlorine gas ( $Cl_2$ ) at 273 K and 1.00 atm?

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Answer 1 · 2016-07-07T21:40:05

$47.0L$

$PV=nRT$ , where $R=0.082057" L atm "mol^-1 K^-1$
$:. V=(nRT)/P$
$V=(2.10molxxRxx273K)/(1.00atm)=47.0L$

What is the volume of 2.10 moles of chlorine gas (Cl_2Cl_2) at 273 K and 1.00 atm?