Question

What is the volume of `9.783*10^23` atoms of Kr at 9.25 atm and 512K?

Answer 1

`V~=7.5*L`

Explanation:

`V=(nRT)/P`
`=(9.783xx10^23*cancel"atoms of Kr")/(6.022xx10^23*cancel"atoms of Kr"*cancel(mol^-1))xx0.0821*L*cancel(atm*K^-1*mol^-1)xx512*cancelKxx(1/(9.25*cancel(atm)))=??L`

The expression is dimensionally consistent. I wanted an answer in `L`, and the expression gave me such an answer.