What is the wavelength of light (in nm) if 1.21⋅1021 photons have a total energy of 483J?

1 Answer
1s2s2p
Jan 31, 2018

λ=498nm

Explanation:

First, we need to know the energy of one photon (assuming they all have the same energy).

Energy of one photon=4831.21⋅1021≈3.99⋅10−19J

E=hf=hcλ

3.99⋅10−19=(6.63⋅10−34)(3⋅108)λ

λ=(6.63⋅10−34)(3⋅108)3.99⋅10−19=4.98⋅10−7m=498nm

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