What is the width of a rectangle if the diagonal is 28 and the length is 19?

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Answer 1 · 2016-06-29T16:17:58

$w = 3 \sqrt{47}$ $w = 3sqrt47$

width $= 20.57$ $= 20.57$

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The diagonal of a rectangle creates a right triangle, allowing us to use the Pythagorean Theorem to solve for the missing side.

$a^{2} + b^{2} = c^{2}$ $a^2+b^2=c^2$

$w^{2} + l^{2} = d^{2}$ $w^2 + l^2 =d^2$

$d = 28$ $d=28$
$l = 19$ $l=19$
$w = ?$ $w=?$

$w^{2} + 19^{2} = 28^{2}$ $w^2+19^2=28^2$

$w^{2} + 361 = 784$ $w^2+361=784$

$w^2cancel(+361) cancel(-361)=784 - 361$

$w^2 = 423$

$w=sqrt423$

$w=sqrt(3*3*47)$

$w = 3sqrt47$

width $= 20.57$