What is the x and y intercept for x - 2y = 8?

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What is the x and y intercept for x - 2y = 8?

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Answer 1 · 2015-08-15T14:15:34

$x$ $x$ -intercept: $(8, 0)$ $(8,0)$
$y$ $y$ -intercept: $(0, - 4)$ $(0,-4)$

Explanation:

For a general equation of a line written in point-slope form

$y = m x + b$ $color(blue)(y = mx + b)$

the $x$ $x$ -intercept can be found by finding the value of $x$ $x$ that satisfies the condtiion $y = 0$ $y=0$ , and the $y$ $y$ -intercept can be found by evaluating the function for $x = 0$ $x=0$ .

In your case, you have

$x - 2 y = 8$ $x - 2y = 8$

You can rearrange this equation into slope-point form if you want

$- 2 y = - x + 8$ $-2y = -x + 8$

$y = \frac{1}{2} x - 4$ $y = 1/2x - 4$

So, for the $x$ $x$ -intercept, you need

$y = \frac{1}{2} x - 4 = 0$ $y = 1/2x -4 = 0$

$\frac{1}{2} x = 4 \Rightarrow x = 8$ $1/2x = 4 implies x = 8$

The $x$ $x$ -intercept will thus be $(8, 0)$ $(8, 0)$ .

For the $y$ $y$ -intercept, you substitute $x = 0$ $x=0$ into the equation

$y = \frac{1}{2} \cdot (0) - 4$ $y = 1/2 * (0) - 4$

$y = - 4$ $y = -4$

The $y$ $y$ -intercept will thus be $(0, - 4)$ $(0, -4)$ .

graph{1/2x - 4 [-14.24, 14.24, -7.12, 7.12]}

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What is the x and y intercept for x - 2y = 8?

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