What is $x$ $x$ if $2 x - \frac{3}{x} = 11$ $2x-3/x=11$ ?

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Answer 1 · 2015-10-28T22:26:44

$x = \frac{11 + \sqrt{145}}{4}, \frac{11 - \sqrt{145}}{4}$ $x=(11+sqrt145)/4, (11-sqrt 145)/4$

$2 x - \frac{3}{x} = 11$ $2x-3/x=11$

Multiply both sides by the LCD $x$ $x$ .

$2x(x)-3/cancelx(cancel x)=11(x)=$

$2x^2-3=11x$

Move all terms to the left side.

$2x^2-3-11x=0$

Rearrange the terms.

$2x^2-11x-3$

$2x^2-11x-3$ is in the form of a quadratic equation $ax+bx+c$ , where $a=2, b=-11, and c=-3$ .

Quadratic Formula

$x=(-b+-sqrt(b^2-4ac))/(2a)=$

$x=(-(-11)+-sqrt((-11^2)-(4*2*-3)))/(2*2)=$

$x=(11+-sqrt(121+24))/4=$

$x=(11+-sqrt(145))/4$

Solve for $x$ .

$x=(11+sqrt145)/4, (11-sqrt 145)/4$

What is xxx if 2x-3/x=112x−3x=112x-3/x=11?