What is x if $log_3(x) +log_2(x+6)=3$ ?

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Answer 1 · 2018-03-12T16:27:57

$1.18" "$ approx

In general $" " log_b a" can be written as " loga/logb$

$log_3(x)+log_2(x+6)=3" can be written as " logx/log3+log (x+6)/log2=3$

$log2*logx+log3*log (x+6)=3log2*log3$

$logx^log2=log8^log3-log (x+6)^log3$

$logx^log2=log (8/(x+6))^log3$

Antilog both sides...

$x^log2=(8/(x+6))^log3$

I guess, it can be solved by graphing... desmos desmos

What is x if log_3(x) +log_2(x+6)=3log_3(x) +log_2(x+6)=3?