What kind of solutions does $3 x - 4 y = 13$ $3x-4y=13$ and $y = - 3 x - 7$ $y=-3x-7$ have?

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What kind of solutions does $3 x - 4 y = 13$ $3x-4y=13$ and $y = - 3 x - 7$ $y=-3x-7$ have?

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Answer 1 · 2018-05-10T17:06:57

The kind of solutions to this equations is that they are unique.
You can either solve it using Gaussian elimination or using substitution method.

Explanation:

$3 x - 4 (- 3 x - 7) = 13$ $3x-4(-3x-7)=13$
$3 x + 12 x + 28 = 13$ $3x+12x+28=13$
$15 x = - 15$ $15x = -15$
$x = - 1$ $x=-1$
Hence,
$y = - 3 (- 1) - 7$ $y = -3(-1)-7$
$y = - 4$ $y=-4$
Substitute the above values for x,y in the equations above to confirm ur answer.

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What kind of solutions does $3 x - 4 y = 13$ $3x-4y=13$ and $y = - 3 x - 7$ $y=-3x-7$ have?

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Explanation:

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What kind of solutions does 3x-4y=133x−4y=133x-4y=13 and y=-3x-7y=−3x−7y=-3x-7 have?

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What kind of solutions does $3 x - 4 y = 13$ $3x-4y=13$ and $y = - 3 x - 7$ $y=-3x-7$ have?