What mass of magnesium oxide is formed when 6 g of magnesium reacts with oxygen?

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What mass of magnesium oxide is formed when 6 g of magnesium reacts with oxygen?

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Answer 1 · 2016-10-11T05:53:10

Approx. a $10 \cdot g$ $10*g$ mass is formed.

Explanation:

$M g (s) + \frac{1}{2} O_{2} (g) \to M g O (s)$ $Mg(s) + 1/2O_2(g) rarr MgO(s)$

$Moles of metal$ $"Moles of metal"$ $=$ $=$ $\frac{6.0 \cdot g}{24.31 \cdot g \cdot m o l^{- 1}}$ $(6.0*g)/(24.31*g*mol^-1)$ $=$ $=$ $0.247 \cdot m o l$ $0.247*mol$ .

And thus there are $0.247 \cdot m o l \times 40.3 \cdot g \cdot m o l^{- 1}$ $0.247*molxx40.3*g*mol^-1$ $magnesium oxide$ $"magnesium oxide"$ $≅$ $~=$ $10 \cdot g$ $10*g$

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What mass of magnesium oxide is formed when 6 g of magnesium reacts with oxygen?

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