What mass of nitrogen dioxide is produced by the reaction of 8.735g of copper with nitric acid?

1 Answer
Meave60
Jul 3, 2018

"12.65 g NO"_2"12.65 g NO2 can be produced.

Explanation:

Start with a balanced equation.

"Cu(s) + 4HNO"_3("aq")"Cu(s) + 4HNO3(aq)rarr→"Cu(NO"_3)_2("aq") + "2NO"_2("g") + "2H"_2"O(l)"Cu(NO3)2(aq)+2NO2(g)+2H2O(l)

Calculate mol "Cu"Cu by dividing its given mass by its molar mass ("63.546 g/mol")(63.546 g/mol). Do this by multiplying by the inverse of its molar mass (mol/g). Then multiply by the mol ratio between "Cu"Cu and "NO"_2"NO2 in the balanced equation, with "NO"_2"NO2 in the numerator. Then calculate the mass of "NO"_2"NO2 by multiplying by the molar mass of "NO"_2"NO2, ("46.005 g/mol")(46.005 g/mol).

8.735color(red)cancel(color(black)("g Cu"))xx(1color(red)cancel(color(black)("mol Cu")))/(63.546color(red)cancel(color(black)("g Cu")))xx(2color(red)cancel(color(black)("mol NO"_2)))/(1color(red)cancel(color(black)("mol Cu")))xx(46.005"g NO"_2)/(1color(red)cancel(color(black)("mol NO"_2)))="12.65 g NO"_2"

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