What mass of steam at #100^@ C# must be mixed with #150 g# of ice at its melting point, in a thermally insulated container to produce water of #50^@ C#?

1 Answer
Shwetank Mauria
Apr 25, 2018

#33.45# grams of steam.

Explanation:

Let it be #x# grams of steam. As latent heat of steam to water is #533# calories per gram, when it converts to water at #50^@C#, it looses heat given by

#533x+50x=583x#

and as latent heat of ice to water is #80# calories per gram, when it converts to water at #50^@C#, it gains heat given by

#150xx80+150xx50=12000+7500=19500#

Therefore, we must have #583x=19500# - assuming that there is no loss of heat to environment and

hence #x=19500/583=33.45g#

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