Question

What pressure (in atmospheres) is required to compress 1.00 L of gas at 760. mm Hg pressure to a volume of 50.0 mL?

Answer 1

`"20 atmospheres........"`

Explanation:

`P_1V_1=P_2V_2`, now `P_1=1*atm`, and so we solve for `P_2`:

`P_2=(P_1V_1)/V_2=(1.00*cancelLxx1*atm)/(0.050*cancelL)=??atm`