What pressure will be exerted by 2.01 mol hydrogen gas in a 6.5 L cylinder at 20°C?

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Answer 1 · 2017-05-05T15:34:10

#P=(nRT)/V=#, which equation is this? I get approx. #6*atm#

#P=(nRT)/V=(2.01*molxx(0.0821*L*atm)/(K^-1*mol^-1)xx293*K)/(6.5*L)#

#=??*atm#.

You should check to make sure that all the dimensions in the expression cancel to give an answer in #atm#. Does they?