What's the net force acting on an 18-kg object if the net force causes an acceleration of 3.0 m/s2?

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What's the net force acting on an 18-kg object if the net force causes an acceleration of 3.0 m/s2?

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Answer 1 · 2015-10-01T22:23:06

The net force is $54 N$ $54"N"$ .

Explanation:

The net force acting on an object is determined by multiplying the mass in kg times its acceleration in ${m/s}^{2}$ $"m/s"^2"$ , or $F_{net} = m a$ $"F"_"net"=ma"$ .

Known:
$m = 18 kg$ $m=18"kg"$
$a = 3.0 {m/s}^{2}$ $a=3.0"m/s"^2$

Unknown:
$F_{net}$ $"F"_"net"$

Equation:
$F_{net} = m a$ $"F"_"net"=ma"$

Solution:

$F_{net} = 18 kg \times 3.0 {m/s}^{2} = 54 N$ $"F"_"net"=18"kg"xx3.0"m/s"^2=54 "N"$

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What's the net force acting on an 18-kg object if the net force causes an acceleration of 3.0 m/s2?

1 Answer

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