Question

What sound intensity corresponds to 92 db?

Answer 1

`0,00158W//m^2`

Explanation:

Sound level `beta = 10log(I/(I_0))`, where `I_0` is the threshold or reference intensity corresponding to the minimum sound that a normal human ear can hear and is assigned a value of `10^(-12) W//m^2`

So in this case, `92=10log(I/(10^(-12)))`

`therefore I=10^(9,2)*10^(-12)=10^(-2,8) W//m^2`