What the is the polar form of $y = y/x+(x+2)(y+1)$ ?

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Answer 1 · 2017-12-02T13:52:16

$sintheta+r^2cos^2thetasintheta+rcos^2theta+1/2rsin2theta+2costheta=0$

We use the fact that:

$x=rcostheta$ and $y=rsintheta$ .

These can be substituted into the equation.

First expand the brackets of.

$y=y/x+(x+2)(y+1)$

$y=y/x+xy+x+2y+2$

Substituting:

$rsintheta=(rsintheta)/(rcostheta)+rcosthetarsintheta+rcostheta+2rsintheta+2$

Simplify:

$0=sintheta+r^2cos^2thetasintheta+rcos^2theta+1/2rsin2theta+2costheta$

What the is the polar form of y = y/x+(x+2)(y+1) y = y/x+(x+2)(y+1) ?