What volume does 4.68 g $H_{2} O$ $H_2O$ occupy at STP?

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Answer 1 · 2016-02-09T01:39:42

The volume of liquid water at 0 °C is $4.68 mL$ $"4.68 mL"$ , and the volume of ice at 0 °C is ${5.10 cm}^{3}$ $"5.10 cm"^3$ .

At 0 °C, water can be a liquid or a solid.

Liquid water at 0 °C

The density of liquid water at 0 °C is $0.9998 g/mL$ $"0.9998 g/mL"$ .

The volume is given by

$4.68 color(red)(cancel(color(black)("g"))) × "1 mL"/(0.9998 color(red)(cancel(color(black)("g")))) = "4.68 mL"$ .

Ice at 0 °C

The density of ice at 0 °C is $"0.9170 g/cm"^3$ .

The volume is given by

$4.68 color(red)(cancel(color(black)("g"))) × ("1 cm"^3)/(0.9170 color(red)(cancel(color(black)("g")))) = "5.10 cm"^3$ .

What volume does 4.68 g H_2OH2OH_2O occupy at STP?