What volume does 7.54 * 10^25 atoms Ne occupy at STP?

1 Answer
Feb 20, 2016

Simple,
First conver 7.54 xx 10^25 atoms of Ne to moles

To do this, use the equation
Number of particles = Number of moles x Avogadro's constant

Since what we have to find out here is number of moles, rearrange the equation and solve for number of moles

Number of moles = Number of particles/Avogadro's Constant
=7.54 xx 10^25//6.02 xx 10^23
= 125.24
Thus, there are 125.24 moles in 7.54 xx 10^25 atoms of Ne

Now, the volume of anything at STP is equal to the number of moles multiplied by 22.4 L

Volume(at STP) = No. of moles x 22.4
= 125.24 xx 22.4
= 2805 L//mol
Thus, the volume is 2805 L/mol at STP for neon