What volume is occupied by 0.695 mol of CO_2 at 342.3 K and 629 mmHg?

1 Answer
Mar 5, 2017

V~=24*L

Explanation:

We use the relationship "760 mm Hg "-=" 1 atm." And then we apply the Ideal Gas Equation,

V=(nRT)/P = (0.695*molxx0.0821*(L*atm)/(K*mol)xx342.3*K)/((629*mm*Hg)/(760*mm*Hg*atm^-1))

=??L