What volume (mL) of a concentrated solution of sodium hydroxide (6.00 M) must be diluted to 200.0 mL to make a 0.880 M solution of sodum hydroxide?

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What volume (mL) of a concentrated solution of sodium hydroxide (6.00 M) must be diluted to 200.0 mL to make a 0.880 M solution of sodum hydroxide?

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Answer 1 · 2016-10-18T15:30:48

Approx. $30.0 \cdot m L$ $30.0*mL$

Explanation:

We require a $200.0 \cdot m L$ $200.0*mL$ volume of $0.880 \cdot m o l \cdot L^{- 1}$ $0.880*mol*L^-1$ $N a O H (a q)$ $NaOH(aq)$ .

$Moles of NaOH = 200.0 \times 10^{- 3} L \times 0.880 \cdot m o l \cdot L^{- 1} = 0.1760 \cdot m o l$ $"Moles of NaOH"=200.0xx10^(-3)Lxx0.880*mol*L^-1=0.1760*mol$ .

We have $6.00 \cdot m o l \cdot L^{- 1}$ $6.00*mol*L^-1$ $N a O H$ $NaOH$ available, and thus $\frac{0.1760 \cdot m o l}{6.00 \cdot m o l \cdot L^{- 1}}$ $(0.1760*mol)/(6.00*mol*L^-1)$ $=$ $=$ $0.0293 \cdot L$ $0.0293*L$ of the original solution must be diluted to a $200.0 \cdot m L$ $200.0*mL$ volume.

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What volume (mL) of a concentrated solution of sodium hydroxide (6.00 M) must be diluted to 200.0 mL to make a 0.880 M solution of sodum hydroxide?

1 Answer

Explanation:

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