Question

What volume of 0.0500M KOH solution is required to completely neutralize 3.0 mL of 0.17M H2SO4?

What volume of 0.0500M KOH solution is required to completely
neutralize 3.0 mL of 0.17M H2SO4?

Answer 1

`(x.C_M .V)_(base) = (y.C_M .V)_(acid)`

Explanation:

Acid-base neutralization

`(x.C_M .V)_(base) = (y.C_M .V)_(acid)`

`C_M = Molarity`

`x= "number of mol ions " OH^(-) "in the formula."`

`y ="number of mol ions " H^+"in the formula."`

`V_(base)= ((y.C_M .V)_(acid))/((x.C_M)_(base))`

`V_(base) = ( 2*0.17 " M "3.0 " mL")/(1*0.0500" M")`

`V_(base) ~= 20. "mL"`