What volume of 0.200 M K2C2O4 is required to completely react with 30.0 mL fo 0.100 M Fe(NO3)3?

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Answer 1 · 2017-05-09T17:17:05

22.5 ml

$sf(2Fe(NO_3)_3+3K_2C_2O_(4)rarrFe_2(C_2O_4)_(3)+6KNO_3)$

The number of moles of $sf(Fe(NO_3)_3)$ is given by:

$sf(n=cxxv=0.100xx30.0/1000=3.00xx10^(-3))$

From the equation we can see that the number of moles of $sf(K_2C_2O_(4))$ must be 3/2 times this:

$sf(n=3.00xx10^(-3)xx3/2=4.50xx10^(-3))$

$sf(n=cxxv)$

$:.$ $sf(v=n/c=(4.50xx10^(-3))/(0.200)=22.5xx10^(-3)color(white)(x)L)$

$sf(v=22.5color(white)(x)ml)$