Question

What volume of 5.0 M `NaOH` is required to make 100 mL 2.0 M `NaOH`?

Answer 1

`40*mL` of `5.0*mol*L^-1` sodium hydoxide are required.

Explanation:

The `"concentration"xx"volume"` gives answer in amount of substance.

Thus `C_1V_1=C_2V_2`, where `C_1, V_1` are the initial concentrations, volume etc.

We need to find `V_1` `=` `([C_1][V_2])/([C_2])`

`=(2.0*mol*L^-1xx0.100*L)/(5.0*mol*L^-1)` `=` `??*L=??*mL`